# 1 Count feeding Funky Bookends and Why Not? 10 Clubs

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1 Count feeding Funky Bookends and Why Not? 10 Clubs's Properties |
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Number of Objects | 10 | Asynchronous | Yes |

Number of Jugglers | 3 | Hurries | No |

Moving | No | ||

Discovered by | Annchen, Berengar, Christoph, Nicki | ||

Prechac | 3.5p 3.5p 3 3.5p 4 | ||

Prechac | 3.5p 3.5p 3.5p 3.5p 3.5p | ||

Prechac | 4 1 3.5p 3 3.5p | ||

Sequence | P P S P S2 | ||

Sequence | P P P P P | ||

Sequence | S2 Z P S P |

There comes a time when all three passers throw almost simultaniously through the center of the pattern, the feedies with diagonal passes from the outside and the feeder with inside passes. This regularly caused collisions with Christoph feeding. With Berengar feeding instead, the collision problem vanished, but we kept moving towards the next wall. :)

Nicki pointed out, that this construction is not limited to three passers. One can attach new passers to create formations N, W, and longer zigzag lines.

- The new feedy brings 3 clubs and throws Why Not?, if he attaches to a former Funky Bookends feedy.
- To extend the pattern at a former Why Not end, one brings 4 clubs and has Funky Bookends.
- In any case, the former feedy turns into a feeder with 1-count.

Said differently: All the inner passers in zigzag line do 1-count. If the number of jugglers is even and ends happen to be on different sides, like in the shape N:

they have both the same pattern, that is either Why Not? or Funky Bookends. With Why Not? the total number of clubs is 3.5 times number of jugglers. With Funky Bookends the total number of clubs is one more than 3.5 times number of jugglers.

With an odd number of jugglers, like in the shape W:

both ends do different things, just as in the 3 person feed. Here one needs half a club less than 3.5 times the number of jugglers.